Multiple files to rename...

[kumariaru]

Hi All,
I need to rename multiple files after copying them to a folder from other folder.

I am getting files in this format..

test_20070513.txt, test1_20070513.txt,...

I want to strip the _ & date and I want file names to be as

test.txt, test1.txt,.....

I am trying to do something like this

cp /tmp/target/* /tmp/source/
echo 'files are moved to source folder'
ls -l |tr 's' '_*.txt' '.txt'
echo 'status=0'
exit 0


I tried to use 'sed' command too. I am not able to get what I need.Please help me in building this script...


Thanks in Advance...

 

[PHV]

One way:

cd /tmp/target
ls *_*.txt | awk '
{x=$0;sub(/_.*\.txt$/,".txt",x);printf "mv %s /tmp/source/%s\n",$0,x}
' | sh -v

Hope This Helps, PH.
FAQ219-2884
FAQ181-2886

 

[PHV]

OOps, sorry for the typo:

cd /tmp/target
ls *_*.txt | awk '
{x=$0;sub(/_.*\.txt$/,".txt",x);printf "[!]cp[/!] %s /tmp/source/%s\n",$0,x}
' | sh -v

 

[kumariaru]

Hi PHV..
Thanks a lot. I am getting below errors when i am executing the below script..


awk: syntax error near line 2
awk: illegal statement near line 2




cd /tmp/target
ls *_*.txt | awk '
{x=$0;sub(/_.*\.txt$/,".txt",x); printf "cp % s /tmp/source
/%s\n",$0,x}
' |sh -v

 

[Annihilannic]

Try nawk instead of awk.

Annihilannic.

 

[PHV]

Replace this:
{x=$0;sub(/_.*\.txt$/,".txt",x); printf "cp % s /tmp/source
/%s\n",$0,x}
with this:
{x=$0;sub(/_.*\.txt$/,".txt",x); printf "cp % s /tmp/source/%s\n",$0,x}

i.e. remove the EndOfLine after source.

 

[kumariaru]

Hi PHV & Annihilannic,
Thanks a lot. The script is working. I changed awk to nawk.

Thank you