Message through email....

[kumariaru]

Good Morning all,
I have a scenario where I need to handle 110 files. I have to get the count of lines of each file individually and need to send an email when the count of the file is 2.
I want to do it in a single script.
For Example:
FILE1 has two lines then I need to send a mail saying that the count of FILE1 is 2.
FILE2 count is more then 2 then no need to send a mail.
FILE3 count is two then I need to send a mail saying that the count of the FILE3 is 2.

Thank you....

 

[feherke]

Hi

One way could be

wc -l * 2> /dev/null | while read nr name; do test $nr -eq 2 && mutt -a "$name" -s "the count of the $name is 2" someone@example.com; done

Feherke.

http://rootshell.be/~feherke/

 

[SamBones]

Another way...

[ignore]wc -l * |sed -n 's/^  *//g;/^2 /p;'|cut -f2 -d' '|mailx -s "Files with two lines" someone@example.com
[/ignore]

 

[dstxaix]

Sam - If the line count is 20, will this command send an email or not?

 

[kumariaru]

Thank you Feherke and Sam...
I will check with both the scripts.....

 

[SamBones]

No, the [tt]sed[/tt] is only allowing lines that start with '2 ' (two and a space). That's the [tt]'/^2 /p'[/tt] part.

 

[SamBones]

Actually, I didn't meet the specs. My solution will send one email with a list of those files that have two lines each. If no files have two lines, an email still gets sent, but there will be no files listed in it.

 

[kumariaru]

Good Morning All,
I have a a problem with wc -l. When I am opening a file with in vi editor I can see 2 lines in it but when I am doing a "wc -l filename" I am getting only 1 as output. It is same with all the files.I am getting word count of total records -1.These files are in DOS format and are moved to UNIX server. I am not understanding why this is happening...

Thanks in advance...