max value in array columns 1

[kjb]

I could not figure out how to write a function that counts elements greater than given max value in columns of a matrix separately.

Can somone help me, pls!
I tried:

int count = 0;
float max = 1.5;
for ( i = 0; i < rows; i++)
for ( j = 0; j < cols; j++)
{
if ( matrix[i][j] > max)
count += 1;
}
[\code]
Above count all the values greater than max but how to report the separately?

Tips/advice would be highly appreciated.

kjb

 

[Basking]

Hi Kjb,

What exactly you want to be reported ?
Do you want the array element to be printed ?
If so try the below code.

int count = 0;
float max = 1.5;
for ( i = 0; i < rows; i++)
for ( j = 0; j < cols; j++)
{
if ( matrix[j] > max)
{
count += 1;
printf(&quot; The maxtrix[%d,%d] value %d is greater than %f\n And count is %d\n, i,j,max,count);
}
}

printf(&quot;No of Elements greater than %f is %d \n&quot;, max, count);

Cheers,
Baskar.


Baskar
baskar52@hotmail.com

http://www.geocities.com/baskar52

 

[kjb]

Thanks Basking

Actually I need to find the count of elements greater than
a given value in 'each' column. In case of an array of 3 columns the return should be like:
2 6 4

Regards

kjb

 

[Basking]

I hope the follwoing code helps you.

int count;
float max = 1.5;
for ( j = 0; j < cols; j++)
{
count = 0;
for ( i = 0; i < rows; i++)
{
if ( matrix[j] > max)
{
count += 1;
printf(&quot; The maxtrix[%d,%d] value %d is greater than %f\n And count is %d\n, i,j,max,count);
}
}
printf(&quot;No of Elements greater than %f in column %d is %d \n&quot;, max, j+1, count);
}
}

cheers,
Baskar

Baskar
baskar52@hotmail.com

http://www.geocities.com/baskar52

 

[kjb]

Many thanks Basking

The function you wrote worked like magic!

Have a good day!

kjb

 

[palbano]

Hello all,

It seems to me you need a count for each column if I have followed this LONG thread correctly. So something like this...

int count[cols];
memset(count, 0, sizeof(int) * cols);

float max = 1.5;
for ( r = 0; r < rows; r++)
for ( j = 0; j < cols; j++)
{
if ( matrix[r][j] > max)
count[j]++;
}

Good luck
-pete