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map IP address

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mikeasa

Technical User
Dec 23, 2005
133
US
I need help with a 7200 to map an outside IP address to an internal IP address.
 
For a single address:

conf t
interface fastethernet0/0
ip add 1.2.3.4 255.255.255.255
ip nat inside
exit

interface serial0/0/0
ip add 4.5.6.7 255.255.255.255
ip nat outside
exit

ip nat outside source static (inside 'real' address) (outside 'alias' address)

exit



 
I need to do 3 of them. Never needed to do this before and didnt learn how thanks for your help. This is what is there now.

interface FastEthernet0/0
ip address 65.46.73.146 255.255.255.252
no ip redirects
no ip proxy-arp
ip nat outside
duplex full
speed 10
!
interface FastEthernet0/1
ip address 67.11.79.65 255.255.255.224
ip nat inside
ip dhcp relay information trusted
no ip route-cache
no ip mroute-cache
duplex full
speed auto
!
interface Serial1/0
ip address 69.64.206.2 255.255.255.252 secondary
ip address 192.168.10.2 255.255.255.0
no ip redirects
ip accounting output-packets
no ip route-cache
no ip mroute-cache
dsu bandwidth 44210
framing c-bit
cablelength 224
serial restart_delay 0
 
You need to map three of them to one address or three of them to three addresses? Which needs to be mapped to what?
 
I need to map 3 different outside addresses to 3 different internal addresses

public 67.11.79.20 to private 192.168.0.20
public 67.11.79.21 to private 192.168.0.21
public 67.11.79.22 to private 192.168.0.22
 
Ya a topology would help.

It seems that your FA0/0 port is the outside NAT port and your FA0/1 port is the inside port with your S1/0 port being a T3.

If I had to take a guess I think it'd go something like this:

ip access-list 40 permit 67.11.79.20 0.0.0.0
ip access-list 40 permit 67.11.79.21 0.0.0.0
ip access-list 40 permit 67.11.79.22 0.0.0.0

ip nat pool inside_range 192.168.0.20 192.168.0.22 netmask 255.255.255.0

ip nat outside source list 40 pool inside_range

That's a wild guess..don't implement it. Wait for other responses. I may very well be wrong.

-E
 
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