loop through a file

[anatazi]

hi all
i just have a quick question.
i am writing a script that will check the number of links for each file in the user's directory and output the appropriate message.

here it is:
#!/bin/sh

ls -l >outputfile

HERE IS MYQUESTION: how do I loop through each line of the file outputfile

for (...)
if $2>=2; then
echo "$9 has $2 links."
else
echo "$9 has one link>"
fi

done

thanks a lot

 

[pavNell]

cat outputfile | while read LINE
do
...
...
...
done

where LINE is a variable representing each line.
HTH

 

[vgersh99]

UUOC!

while read LINE
do
...
...
...
done < outputfile vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[anatazi]

Hi all, I tried both of your suggestions and they both work fine however, now my inside loop does not work. It seems that the
if $2>=2; then
echo &quot;$9 has $2 links.&quot;
else
echo &quot;$9 has one link>&quot;

goes looking for agruments in the command line. so the output I get is as follow.
has links.
has links.
has links.
has links.
has links.
has links.
has links.
has links.
has links.
Can someone please point out what I am doing wrong.
Thanks

 

[vgersh99]

ls -l /tmp | nawk '{ printf(&quot;%s has %d link%s\n&quot;, $9, $2, ($2 >= 2) ? &quot;s&quot; : &quot;&quot
;}'
vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+