julian date help

[encourage]

how do i convert gregorian date to equivalent julian date in
C shell

 

[olded]

encourage:

I've never seen a good solution to this question in unix shell. Over the years, I've collected several utilities in "C" (written by guys smarter than me) that answer this question, and other date related questions.

Provide an email address, and I'll send you the "C" source.

Regards,


Ed
Schaefer

 

[encourage]

olded,

thanks a lot for ur response .

my email address is sunbaj@mailcity.com

hope to recieve a repply from u as early as possible

regards
sunil

 

[StevetheBlue]

This works in ksh assuming a command line parameter of a valid date in the format YYYYMMDD.

#!/bin/ksh

yr=$(echo $1 | cut -c1-4)
mth=$(echo $1 | cut -c5-6)
day=$(echo $1 | cut -c7-8)

while [ $mth -gt 1 ]; do
mth=$(($mth - 1))
set $(cal $mth $yr)
shift $(($# - 1))
day=$((day + $1))
done

echo $(printf "%4d%.3d" $yr $day)