Is it possible to open a specific file when invoking an application?

[beck4525]

When invoking an application using the Runtime exec() method, is it possible to also open a specific file in the application? For example, if you are wanting the user to be able to view a file in Word, I know how to invoke word, but not with the appropriate file open for the user to see.
Many thanks in advance for any help.

 

[donniea21]

How many people will be using this app? Meaning, if you hardcode a path for a document, there is not gurantee that the document will reside in the same folder, on the same drive letter, etc. IF that is not a problem, something like

Runtime.getRuntime().exec("C:\\Program
Files\\MSOffice\\Winword\\WINWORD.EXE d:\\usr\\ray\\java\\q7\\documentname.doc"


might work

 

[beck4525]

Thanks very much donniea21. Your suggestion works when I type in the path as suggested...

Runtime.getRuntime().exec("C:\\Program Files/Microsoft Office/Office/Winword.exe test.doc"

If the file name (test.doc) was stored in a String variable, how would I include that instead of hard-typing "test.doc"???
Many thanks again
beck4525

 

[donniea21]

Im not really sure but you may be able to store the string for the application in a string and the doc name in another and then concat them

String wordApp = "C:\\Program Files/Microsoft Office/Office/Winword.exe";

String docName = "test.doc";

Runtime.getRuntime().exec(wordApp + " " + docName);

 

[donniea21]

Realized that you don't really need to use 2 variables.

String docName = "test.doc";

java.lang.Runtime.getRuntime().exec("C:\\Program Files/Microsoft Office/Office/Winword.exe " + docName);

note the space after .exe

this should work for ya.