If statment with or 1

[ginger32]

ok here we go!

I have an if statment with multiple 'or' conditions. The only problem is a can not get my if to see any of the or stantments past the first one!if [ "`logname`%" = "dev3%" or "`logname`%" = "devel1%" or "`logname`%" = "icdevel%" ]
then
if [ `who |grep $LOGNAME |wc -l` -gt 3 ]
then
echo "You will be disconnected due to too many logins plus 3"
sleep 5
exit
fi

the if picks up dev3 but not devel1 or icdevel!

 

[mrregan]

Try
if [ "`logname`%" = "dev3%" -o "devel1%" -o "icdevel%" ]

 

[Boria]

Hi,
"-o" is well for integer. For strings you must use "||" for logical OR instead.
Regards Boris

 

[ginger32]

Now if always maches the case...

ie

if dev1 logins in he gets 3 logins where all i want is 1 login for dev1

 

[ginger32]

This was how i did it!!!
if [ ! "`logname`%" = "devel%" -a ! "`logname`%" = "dev1%" ]
then
if [ "`logname`%" = "dev3%" -o "`logname`%" = "devel1%" -o "`logname`%" = "icdevel%" ]
then
if [ `who |grep $LOGNAME |wc -l` -gt 3 ]
then
echo "You will be disconnected due to too many logins. "
echo "You are allowed to log in 3 times."
sleep 5
exit
fi
else
if [ `who |grep $LOGNAME |wc -l` -gt 1 ]
then
echo "You will be disconnected due to too many logins."
echo "you are allowed 1 login"
sleep 5
exit
fi
fi
fi

 

[akkie]

Hi,

Why not try to solve this with a CASE construction similar to this:

case `logname` in
devel|dev1)
instructions
;;
dev3|devel1|icdevel)
other instructions
;;
esac

Are the % characters to check if the variable exists?

Regards,
Willem

 

[J1mbo]

the korn shell provides a nice way to do multiple 'or' conditions with an 'if' statement:

if [[ "`logname`%" = @(dev3|devel1|icdevel)% ]] ; then

..do stuff

fi


-jim