I need help reading a file

[yaway]

I have a file with two lines for data and I need to search the file for only one word. If I find the work I need to run a script (Which I have already) if not I need the program to do nothing.

The word I am looking for is ONLINE.

Thank You
Yaway

 

[newmangj]

Why not just use grep, or am I missing something significant.

Something along the lines of....

#!/bin/bash
grep ONLINE myfile_name > /dev/null 2> /dev/null
if [[ $? == 0 ]]
then
echo "ONLINE FOUND - RUNNING SCRIPT"
/dir/dir/script_to_be_run
exit 0
fi
echo "ONLINE NOT FOUND - NO ACTION TAKEN"
exit 1

 

[yaway]

Nothing happens when I run this script. I must be doing something wrong. I do not even get the echo to work.

 

[AHinMaine]

I'm no bash scripter, but translating it to regular bourne shell would be something like:

#!/bin/sh
CHECK=`grep ONLINE myfile_name`
if [ -n "$CHECK" ]
then
    #do stuff
fi

--
Andy

http://www.nachoz.com

 

[AHinMaine]

Oops, let's try that again...

#!/bin/sh
CHECK=`grep ONLINE myfile_name`
if [ -n "$CHECK" ] ; then
    #do stuff
fi

--
Andy

http://www.nachoz.com

 

[yaway]

When I run the script I get an error 'then' is not expected.

 

[yaway]

I found the problem with the then statement. When I run the script I get errors that it can not find ONLINE. The input file looks like this


blank line
This is currently the ONLINE side.
This is the B side.

Any help would be great.
Thank You

 

[newmangj]

Please post your script in full....

 

[Ygor]

Also try.....

grep -q ONLINE myfile && echo found || echo not found