How to open the "Open File" dialog box with VBA...? 1

[estiguar]

Hi there!
Does somebody know how I can open the "Open file" dialog box with VBA?
What I want to do is to select a file on the network and save the path in a variable in VBA. Is this possible? And if yes, how can I do that?
Many thanks,
Roberto

 

[PantoKing]

Hello,
Paste the code that follows in to a new module and use the following syntax to run the function
GetFileBox(Initial Path, Dialog Box Title, Filter) e.g Getfilebox("c:\","Open File","*.mdb&quot.

------Code Starts---------

Option Compare Database
Option Explicit

Public lngRowNumber As Long 'Stores the row number where the data error has occured
Public lngRecordCount As Long 'Stores the total record count

'
'Module to Open a Windows File Dialog Box.
'
'Function uses "comdlg32.dll" and therefore will work with Access '97 and 2000
'
'Functions Included :
'
'OpenAccessFile
'SaveAccessFile
'OpenAnyFile
'SaveAnyFile
'OpenTextFile 'Text File includes option to open/save CSV file.
'SaveTextFile
'
'Just call the function with optional initial directory(Default = C:\)
'Selected Filepath and Name will be returned.
'
'Origin of API code unknown.

Public Declare Function GetOpenFileName Lib "comdlg32.dll" Alias "GetOpenFileNameA" (pOpenfilename As OPENFILENAME) As Long
Public Declare Function GetSaveFileName Lib "comdlg32.dll" Alias "GetSaveFileNameA" (pOpenfilename As OPENFILENAME) As Long


Public Type OPENFILENAME
lStructSize As Long
hwndOwner As Long
hInstance As Long
lpstrFilter As String
lpstrCustomFilter As String
nMaxCustFilter As Long
nFilterIndex As Long
lpstrFile As String
nMaxFile As Long
lpstrFileTitle As String
nMaxFileTitle As Long
lpstrInitialDir As String
lpstrTitle As String
flags As Long
nFileOffset As Integer
nFileExtension As Integer
lpstrDefExt As String
lCustData As Long
lpfnHook As Long
lpTemplateName As String
End Type



Function GetFilebox(strInitialD As String, strTitle As String, strFilter As String) As String

On Error GoTo ERR_GetFilebox

Dim OpenFile As OPENFILENAME
Dim lReturn As Long
Dim sFilter As String
OpenFile.lStructSize = Len(OpenFile)
OpenFile.hwndOwner = Screen.ActiveForm.Hwnd
OpenFile.lpstrFilter = strFilter
OpenFile.nFilterIndex = 1
OpenFile.lpstrFile = String(257, 0)
OpenFile.nMaxFile = Len(OpenFile.lpstrFile) - 1
OpenFile.lpstrFileTitle = OpenFile.lpstrFile
OpenFile.nMaxFileTitle = OpenFile.nMaxFile
OpenFile.lpstrInitialDir = strInitialD
OpenFile.lpstrTitle = strTitle
OpenFile.flags = 0

lReturn = GetOpenFileName(OpenFile)
If lReturn = 0 Then
GetFilebox = ""
Else
GetFilebox = Trim(OpenFile.lpstrFile)
End If

Exit_GetFilebox:

Exit Function

ERR_GetFilebox:

Select Case Err.Number

Case 2475
OpenFile.hwndOwner = 0
Resume Next
Case Else
MsgBox "Error : " & Err.Number & vbCr & vbCr & Err.Description
End Select

Resume Exit_GetFilebox

End Function


Make things as simple as possible — but no simpler.

 

[estiguar]

This is EXACTLY what I was looking for! GREAT! Thanks so much...
Cheers,
Roberto