how to manipulate more than one variables in a loop

[huangwason]

for instance, print out something like:

400 202 402 204 404 206 ...

what I am thinking is use one variable manipulates digits begin with 4, another variable for digits begin with 2.
for ((i=0,j=1;i<=2,j<=3;i++,j++));do
printf "%s %s" 400+$i*2 200+$j*2
done

the problem is that it looks like i and j are always in the same length, the above code can not output like

400 202 402 204 404 206 208 210 212

any proposal? thanks first

 

[PHV]

Something like this ?

awk 'BEGIN{for(i=0;i<=9;++i)printf "%s %s ",400+i*2,202+i*2;printf "\n"}'

Hope This Helps, PH.
FAQ219-2884
FAQ181-2886

 

[huangwason]

thanks PHV, but it does not match my requirment, I can not obtain the output such as
400 202 402 204 404 206 208 210 212

 

[feherke]

Hi

Note that the second parameter must be a single expression. And using the needless multiplication just slows it down.

for ((i=400,j=202;i<=404||j<=206;i+=2,j+=2)); do
  printf "%s %s " $i $j
done

To solve your problem I see no nice solution, only this :

for ((i=400,j=202;i<=404||j<=212;i+=2,j+=2)); do
  [ $i -le 404 ] && printf "%s " $i
  [ $j -le 212 ] && printf "%s " $j
done

Feherke.

http://rootshell.be/~feherke/

 

[huangwason]

thanks guys, my original intention is to out put something like
430 432 434 436 002 430 432 434 436 004 430 432 434 436 006 430 432 434 436 008 430 432 434 436 00a 430 432 434 436 00c ...

I found a easy way only use one variable in the for loop, and print the second variable when it accumulate. Thanks again. A piece of code looks like

let m=1
for ((j=1;j<=$16;j++)); do
for ((k=0;k<4;k++)); do
printf "%x " 4$(echo "(48+$i*2)+$k*2" | bc)
done
[ $m -le 195 ] && printf "%x " $m
let m+=2
done