how to grep this??

[dvknn]

Hi,

I have lines in my log files like this.

1,"0999"4000,"gg0002ba39"117,"AE"50,"US"24,"20040711"0,"621"4128,"000000"4131,"000000"68,
"USD"80-1,"US"99,""

I want to grep the '117,"AE"50,"US"' this part from the file.

How can I do that?

 

[PHV]

Something like this ?
fgrep '117,"AE"50,"US"' /path/to/logile
or I'm missing something ?

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244

 

[dvknn]

In the string

1,"0999"4000,"gg0002ba39"117,"AE"50,"US"24,"20040711"0,"621"4128,"000000"4131,"000000"68,
"USD"80-1,"US"99,""

I do not have any spaces..Does fgrep allow to grep from the full string??

So, could you please explain fgrep?

 

[vgersh99]

this is a bit confusing.
Pls post a sample input and a desired output.


vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[PHV]

First, feel free to play with the man command.
Next, I don't quite understand your question.
What do you want to do ?
Find the lines in the log file that contain the specified pattern ?
Do substrings manipulations ?
Can you please post some input values examples with corresponding expected result ?

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244

 

[stefanwagner]

If the length of the output is allways the same, colrm should do a great work.

cat logfile | colrm 1, 25 | colrm 16 > values

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