How to get file's name?

[volcano]

Hello guys and gals, I have gone through most of the thread. It seems my question may be too simple to be asked here

My case is that I have some PDFs in my directory under Solaris OS. I want to write a (Bourne) shell script to get those PDF file names and store in variables. So how could I do this? I need these names to fax the PDFs. But I couldn't hard-code those names.

Thanks!

 

[J1mbo]

You can store them in a loop to be processed individually:

for EACHPDF in `find /directory/path -name "*.PDF"` ; do
echo $EACHPDF
done


-jim

 

[volcano]

Thanks Jim! That's exactly what I need.

 

[TimeTraveler]

If you want to limit to the current directory, this might work.
It's not as elegant, granted.

#!/bin/sh
# limiting to cur dir unlike 'find' command
for EACHPDF in `ls -1 *.PDF *.pdf 2>out.err`
do
echo $EACHPDF
done # with EACHPDF

It also would allow something like this:

#!/bin/sh
# limiting to cur dir unlike 'find' command, and grepping for 'march'
# assuming dir contains something like this: ls -1 *.pdf
# february-week-4.pdf
# march-week-1.pdf
# march-week-2.pdf
# etc.
for EACHPDF in `ls -1 *.PDF *.pdf 2>out.err | grep -i march`
do
echo $EACHPDF
done # with EACHPDF


Granted, this is probably overkill. -S Visit

http://www.museworksentertainment.com

 

[volcano]

Thanks TimeTraveler