How to count words in a file??? 2

[mremoos]

Hi, I need to write an awk script that would count the words in a file and print the result. I don't know what kind of command would do that.
I am a beginner and I could really use some help.
Thank you.

 

[PHV]

To count the number of words:

awk '{t+=NF}END{print t," words"}' /path/to/file

To count the number of time words appear:

awk '{for(i=1;i<=NF;++i)++w[$i]}
END{for(t in w)print w[t],t}' /path/to/file

Hope This Help
PH.

 

[CaKiwi]

Or

wc -w filename

CaKiwi

"I love mankind, it's people I can't stand" - Linus Van Pelt

 

[mremoos]

Thanks for answering so quickly.
The wc -w command works fine, it's just not exactly what I need.
In fact, I need to count the number of words in a file, ignoring the lines that begin with ";" .
Thanks again.

 

[CaKiwi]

Try

grep -v "^;" filename | wc -w

CaKiwi

"I love mankind, it's people I can't stand" - Linus Van Pelt

 

[mremoos]

the last one works just fine.
Now, I am still trying to change this one: grep -v "^;" filename | wc -w ,the one i got from user PHV (Thank you!) I want it to ignore the lines that begin with ";" .
Could use some help.
Thanks a lot.

 

[CaKiwi]

Maybe

awk '!/^;/{t+=NF}END{print t," words"}' /path/to/file


CaKiwi

"I love mankind, it's people I can't stand" - Linus Van Pelt

 

[mremoos]

THANK YOU CAKIWI!!!