How to check if list is nested?

[bokula]

Hi!

How can I check if some list is nested?
I have a list:

mylist = ['a', 'b', 'c']

then I make a change:

mylist[0] = ('a1', 'a2')

Now I have nested list:

[('a1', 'a2'),'b', 'c']

When I want to loop through mylist and print it, I need to check somehow if some list index is nested or not because if yes, printing will be different for nested indexes.

Thanks.

Bosko

 

[flummoxd]

First off, a small nitpick: the square brackets [] are for lists, but the round brackets () are for tuples. As I understand it, tuples are immutable (cannot have their content or structure changed). I bring it up because it affects your solution slightly:

$ python
Python 2.5.1 (r251:54863, May  2 2007, 16:56:35) 
[GCC 4.1.2 (Ubuntu 4.1.2-0ubuntu4)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> mylist = ['a', 'b', 'c']
>>> mylist[0] = ('a1', 'a2')
>>> mylist
[('a1', 'a2'), 'b', 'c']
>>> if (type(mylist[0]) == tuple):
...     print "do tuple logic"
... elif (type(mylist[0]) == list):
...     print "do list logic"
... else:
...     print "do something else"
do tuple logic

I don't know enough about python to know if this is good form or not, but it does work.

 

[bokula]

Hi!

Thanks.
This seems to be simplest and shortest way.

B