How do I open a file with the "Open with" dialog 1

[psnead]

I am opening a file from a windows program. I can open the
file with ShellExecute, but I don't want to specify the type of file, it will be more portable this way. Anyone know how to call the "Open with" dialog that is used in windows so much. I figure it must be an MFC call, but maybe not...

 

[quangdaotran]

You can use ShellExecute, but don't pass directly name of file that you want to open as parameter for ShellExecute. Instead of that, use the following string:
C:\WINDOWS\rundll32.exe shell32.dll,OpenAs_RunDLL FILENAME

You type name of file that you want to open in place of FILENAME in above parameter.

Good luck !

PS. Any further question, contact me:
quangdaotran@yahoo.com