How do I convert Integer to String

[SGLong]

I need to make an adjustment to an old ANSI C application. The original programmer is no longer with us and nobody here has experience with C.

I have an integer value (numofgroups) that I want to convert to a string value (pie_count). I know that there is a 'sprintf' function, but the documentation is extremely poor as to how to call the function. I've tried several variations of this function but keep getting compile errors.

Any suggestions would be greatly appreciated.

 

[palbano]

int numofgroups = 2001;
char buf[256];
sprintf(buf, "%d", numofgroups);
cout << buf << endl;

Hope this helps
-pete

 

[thebigf]

@palbano

cout is C++; It's not possibel with ANSI C.

Use printf instead.

e.g. printf(&quot;%s\n&quot;,buf);

 

[rbobbitt]

or puts() and save yourself some typing:

puts(buf);

Russ
bobbitts@hotmail.com

http://home.earthlink.net/~bobbitts

 

[palbano]

@thebigf,

uh... ooops, my bad.
Thanks for watching my back. B-)

-pete

 

[vkavith]

TO convert a string into integer, you could use itoa function. It is found stdlib.h file.
Similarly atoi will convert a string into an integer.

Hope this helps!

Sriks

 

[SGLong]

Sriks,

That's what I was looking for... thanks

Steve

 

[rbobbitt]

Keep in mind though that itoa() is a non-standard function and a given implementation may or may not support it (i.e. this makes your code less portable).

Russ
bobbitts@hotmail.com

http://home.earthlink.net/~bobbitts

 

[vkavith]

Russ is right... u have to be careful here though.!!

 

[rbobbitt]

...Not to beat a dead horse, but sprintf() is the most portable and simple solution as polbano originally suggested...minus the subsequent cout call ;-)



Russ
bobbitts@hotmail.com

http://home.earthlink.net/~bobbitts

 

[mdktindia]

should you try to make a function convert an integer to a string?

 

[shail]

if u must,

int length, i, j;
char buf[15];
num=numofgroups;
length=log10(num)+1; /*this can be leave one leading byte with a zero in it.*/
memset(buf,'0',15);
for (i=0,j=length; i<length;i++)
{
buf[--j]=num%10;
num /= 10;
}
buf=0;

printf(&quot;\nnow is %d == %s ??\n&quot;, numofgroups, buf);

hth,
shail.

 

[hnd]

Why such complicated?

try:

sprintf(buffer,&quot;%-d&quot;,value);

hnd
hasso55@yahoo.com

 

[lfang]

A revised version based on shail's (tested).

int length, i;
char buf[15];
int num = n;
length=(int)log10+1;
memset(buf,'0',15);
buf[length] = 0;
for (i=length-1; i >= 0;i--)
{
buf += num%10;
num /= 10;
}