Hexadecimal value from String

[puntito]

Hi

My problem is:

I receive a hexadecimal number like a String "ff000001123456"

And I have to say to the program that it is an hexadecimal number.

I´ve tried this:

intValue = Integer.decode("0x"+gaga);

but i have an error


java.lang.NumberFormatException: For input string: "ff000001123456"


and with this:

import com.sun.org.apache.xerces.internal.impl.dv.util.HexBin;
... 
HexBin.decode(text)
...

I have compiling problems with the JAR.

So, I need a method to convert that String to an hexadecimal value.

Someone who know how to do it and could help me??? Please !!!
Thanks

 

[Bong]

User the parseInt method of the Integer class:

parseInt(String s, int radix)
Parses the string argument as a signed integer in the radix specified by the second argument.

with a radix of 16:
int s2i = Integer.parseInt(sstring, 16);, where sstring will be the input string.

_________________
Bob Rashkin

 

[puntito]

mmmmm, thank you, but I already use that option too and my problem continue

java.lang.NumberFormatException: For input string: "0xff000001123456"


But thanks for the quick answear!!

 

[Bong]

Knock off the "0x"?

_________________
Bob Rashkin

 

[puntito]

NOP, SAME RESULT

java.lang.NumberFormatException: For input string: "ff000001123456"

 

[Diancecht]

That number is too large to be an int, use a long

Long j = Long.decode("0xff000001123456");
System.out.println(j.longValue());

Cheers,
Dian