Help with hexadecimals...please! 1

[trojan800]

I have completely forgotten how to convert hexadecimals and while this question isn't directly related to TCP/IP (it is a MAC address), I figured someone here might still be able to help me. It relates to an issue I am having with my VMWare machine. So on to my question...

ethernet[n].address = 00:50:56:XX:YY:ZZ

In this line, XX must be a valid hexadecimal number between 00h and 3Fh, and YY and ZZ must be valid hexadecimal numbers between 00h and FFh.

Could some one please at the very least give me a couple of examples that would work here. Thanks so much for any and all help in advance.
-Rory

 

[SimonDavies]

What you could always do is run Calc from any MS OS and do it from there, all you would need to do is change the view to scientific.

 

[trojan800]

Thanks for the tip Simon, however I have tried using it but still fail to see how... it only shows up to 'F' and beyond that I don't remember how to use the scientific functions anyway. So if you can figure out how and give a quick explanation that would be great.

 

[trojan800]

Somebody...anybody...please?

 

[SimonDavies]

Is this any good then??

http://www.ke4nyv.com/math.htm

or this??

http://www.myhome.org/pg/numbers.html

 

[trojan800]

Simon...here is a star for you! Thanks so much. I was way off. The 'h' at the end of the numbers was throwing me off. While I thought the calculater was off it was in fact that h just notates that they are hexadecimals... of course its very obvious now.

 

[anubaba82]

Hi,

Although the calculator is certainly a faster way to do it. I thought it would be nice to know the manual way of doing it.

A hexadecimal numnber is a Byte (binary representation) divided into two parts...each part having 4 bits. Each part is called a nibble.

So Hexadecimal 50 = 5 + 0 = 0101 + 0000 = 01010000 in binary.

While binary form uses numbers 0 to 9 for representation, hexadecimal form uses Letters A to F additionaly for representing numbers 10 through to 15.

So Hexadecimal 5F would mean 5 + 15 = 0101 + 1111 = 01011111 in binary.

Knowing these representaions can prove to be handy in certain situations.

Rgds