Help with grep command 2

[starla0316]

Hi!

I am trying to do a grep for one of our processes, but would like to know how not to include the command itself.

Ex. ps -ef|grep process
psoftfs 3164 1 4 03:46:45 ? 0:41 ./process INFILE=/directory/process
psoftfs 23269 8530 0 22:20:44 pts/5 0:00 grep process

As you can see, it returns both the output, and the command I issued. I am only interested in getting the particular process.

Also what would be the best command to count for the number of processes running (excluding the grep command itself).

thanks!

 

[hoinz]

man grep,
look at -v option

 

[hoinz]

... and -c option

 

[Martin999]

Include the first character of what you looking for in [].

eg

ps -ef |grep [n]fs
root 651 0 0 Nov 10 ? 0:00 nfskd

Martin

 

[KenCunningham]

ps -ef | grep <process> | grep -v grep

add | wc -l at the end to get a count.

 

[hoinz]

What I thought of was this:
ps -ef | grep -v grep | grep -c <process>

 

[jxmac18]

Martin99 has the most elegant solution. The [] pattern match will exclude your grep process. Although it doesn't handle variables.

--
Jack

 

[3070supporter]

Hi, For the second part of your question, the command "top" usually shows you exactly what is running without using grep, and it uses vi commands to run: j = forward a page, k = back a page, q = quit running top.