Having multiple arrays share a syncroot 2

[robotduck]

I'd like to have three arrays all share the same syncroot, so that in my multi-threaded application, if any thread gets a lock on any one of the 3 arrays, no other thread can modify any of the 3 arrays until the lock is released. Is this possible? is it a really bad idea?

I have tried setting the syncroot of the arrays (which failed, because it's read-only).

any ideas welcomed!

thanks,
Ben

 

[bangerman]

Why not synchronize them yourself? Create your own sync object and use the same one when accessing your arrays?

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[chiph]

If these arrays have to be kept in sync, I would embed your arrays in their own class with it's own getter/setter properties that external callers would use. This class would have it's own internal syncroot object.

This way the actual implementation of how your data is stored is hidden from the callers, and usage becomes transparent to them.

Chip H.


____________________________________________________________________
If you want to get the best response to a question, please read FAQ222-2244 first

 

[robotduck]

Thanks guys, makes perfect sense.

 

[chiph]

If you're using .net v2.0, you might also want to look at the System.Transaction namespace, so that your changes to these arrays can be written to atomically.

Chip H.


____________________________________________________________________
If you want to get the best response to a question, please read FAQ222-2244 first

 

[graabein]

I have a similar problem.

I have some List<MyClass> arrays in memory and I think I have to lock them to get rid of an error, but do I have to lock just for insert and flush, or do I also have to lock on read?

I used this code to help me:

http://www.thescripts.com/forum/post1993530-6.html

My read method goes something like this:

return _changeList.Exists(delegate(ChangeBE e)
{
    return (
        (e.UserName != userName) &&                                          
        (e.ListType.Substring(0, 2) == myListType) &&
        (e.Timestamp > lastChecked)
    );
});

graabein