grep all lines between certain lines 1

[buckpasser]

Folks,

I would like to grep a file such that lines between certain lines are saved to a file.

For instance, grep/save lines between lines starting with "#" and lines starting with ":"

Thanks

 

[feherke]

Hi

Must be [tt]grep[/tt] ? [tt]sed[/tt] or [tt]awk[/tt] would be easier.

sed -n '/^#/,/^:/p' inputfile > outputfile
[gray]# or[/gray]
awk '/^#/,/^:/' inputfile > outputfile

If you search the archive, you will find a lot of threads about this.

Feherke.

http://rootshell.be/~feherke/

 

[Ogzilal]

Hi,

ex /path/to/input_file1>/dev/null 2>&1 <<- EOEX
$
?^#
+1
.,/^:/-1 w! /path/to/output_file
EOEX

 

[feherke]

Hi

That is nice, aau. Looks misterious too, at least for me.

But I do not understand a thing. You wrote [tt]?[/tt] for the search, and this searches backward wrapping around the end of file and find the last # line. Is this the normal/intended way, or just I missed something while tried to follow the steps of your code ?

Feherke.

http://rootshell.be/~feherke/

 

[KarveR]

feherke's awk was quality, so thank you feherke, and a star.

______________________________________________________________________
There's no present like the time, they say. - Henry's Cat.

 

[Ogzilal]

Hi feherke

Yes the search backward is intended when you have more than one line beginning with #.
bukpasser said <lines starting with # and lines starying with : >

I understand with this tha the file may present some lines like this :

1111
2222
#33333
#44444
aaaa
bbbb
cccc
:eeee
:ffff

only lines aaaa to cccc will be concerned.

That's is why the last occurrence is searched.

 

[feherke]

Hi

So that is the theory, thanks. Never thinked to this possibility. I looked dumb to your code, because I used abit different input file :

one
# two
three
: four
five
# six
seven
eight
: nine
ten

Feherke.

http://rootshell.be/~feherke/

 

[buckpasser]

Thanks, that was a big help!