Hello,
When I do a ls -l command, the 5th column gives me the file size. How do I extract this column using cut or some other command.
I am a novice to awk . How do I do it in awk??
Is there another way to check the file size using scripting???
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.