getting index.html from href

801119 · Jan 30, 2002

Greetings all...

Just wondering, how do I strip down

http://long.url.com/index.html

to everything after .com?
is there a easy way.. or must I create my own script? (that I can, just to laizy to do it right now)

thanks for anyhelp... My codes look like something a kid wrote
I have absolutely no idea what I am talking about
Somehow I still manage to make it work

baad · Jan 31, 2002

hi

i remember some sort of your question,

take a look at thread216-196304

i don't know an easy way.. Victor

doublehelix · Jan 31, 2002

Use a regular expression and extract everything after the last slash.

801119 · Jan 31, 2002

doublehelix...

sicne I'm not used with those expressions I wouldn't know how to make one! (my solution had been a loop *haha*).. could you give me a hint were to start?

and vituz, the thread you pointed towards didn't do what I wanted, it.. (have no idea what it does) but I would guess it checked for the existance of

http://www ?

My codes look like something a kid wrote
I have absolutely no idea what I am talking about
Somehow I still manage to make it work

baad · Jan 31, 2002

nope, there i used *those expressions* to split the url entered apart to
~domain (hostname, before first / symbol, e.g. www.tek-tips.com)
~pathname (here it would be just /)
~filename (viewthread.cfmblabla)

Code:

var _pat1=/([^\/]*)(\/.*)*/
var parts={
_hostname : url.match(_pat1)[1],
_pathname : url.match(_pat1)[2],
_patharr  : url.match(_pat1)[2].split(&quot;/&quot;),
_file     : &quot;&quot;
}
var _temp=parts._patharr
parts._file=_temp[_temp.length-1]
_temp.length--;
parts._pathname=(_temp.length==1) ? &quot;/&quot; : _temp.join(&quot;/&quot;)

//alert(&quot;there are\nhostname: &quot;+parts._hostname+&quot;\npathname: &quot;+parts._pathname+&quot;\nfile: &quot;+parts._file)

some explanations:

var _pat1=/([^\/]*)(\/.*)*/ - a pattern, first brackets matches everything before first /, second - everything else..

url.match(_pat1) - this catches matches of entered url with given pattern, if assigned to a variable (like in my case) it returns an array of matches (the length of array equals to the amount of bracket-qroups [2 in this case] & numbering starts from 1, but not from 0)
so,
url.match(_pat1)[1] would catch the first match (meaning hostname) & second - (blabla[2]) - the second match (pathname)

then i split that pathname by "/" & the last value in resulting array is a filename; i qrab it outta here & join the rest to the "_pathname" variable

blabla (tired explaining)

and so on..

what can i say? i guess it is too complicated.. but i like to write things that might be used in many ways

Victor

doublehelix · Jan 31, 2002

Try this too...

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<html>
<head>
<title>File name Capture from a URL</title>
</head>

<body>
<script language="JavaScript">

var myRegExp=new RegExp();
var myRegExp = /(\/)+/;


var url_temp=window.location;
url_temp=String(url_temp);


var url_array=url_temp.split(myRegExp);


document.write("domain: "+url_array[1]+"<br>&quot

;
document.write("path: &quot

;
for(i=2;i<url_array.length-1;i++)
{
document.write(url_array+"/"
}
document.write("<br>"
document.write("file: "+url_array[url_array.length-1]);

</script>
</body>
</html>

simonchristieis · Feb 6, 2002

function strip(){
var a = "

http://long.url.com/index.html"

var b = new Array();
b = a.split("/&quot

// b[b.count] will be index.html
}

bvallet · Feb 6, 2002

try this:

var path = location.pathname;

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getting index.html from href

801119

Programmer

baad

Programmer

doublehelix

IS-IT--Management

801119

Programmer

baad

Programmer

doublehelix

IS-IT--Management

simonchristieis

Programmer

bvallet

Programmer

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