Get part of string 1

[brownfox]

Here is my string:

(user_id LIKE '%2568%')

And I want to get 2568 from that string. Does anyone know how I could do this?
T.I.A

 

[cLFlaVA]

$string = "(user_id LIKE '%2568%')";
$parts = split( "%", $string );

echo $parts[1];

*cLFlaVA
----------------------------
[tt]a frickin' twelve-gauge, what do you think?[/tt]
[URL unfurl="true"]http://www.coryarthus.com/[/url]

 

[brownfox]

Thanks cLFlaVA!

 

[sylve]

use strpos() to find out if 2568 occurs in your string. It'll return the position of the first character. It will return false if 2568 isnt there.

$result = strpos($yourString, '2568');

preg_match() and strstr() are your alternate choices.

Good luck!

 

[brownfox]

But 2568 is a variable in this case so:
$parts = split( "%", $string );
echo $parts[1];
is the perfect answer