get one specfic word from each line and check that process

[vikassalvi]

Hello,
I have following input file
BIP8099I: UserNameServer - MQSUA02
BIP8099I: MQSUA02 - MQSUA02
BIP8099I: MQSTA01 - MQSTA01
BIP8099I: MQSUA04 - MQSUA04
BIP8099I: MQSUA99 - MQSUA99
BIP8099I: MQSSA02 - MQSSA02
BIP8099I: MQSTA04 - MQSTA04
BIP8099I: MQSSA04 - MQSSA04
BIP8071I: Successful command completion.
what I want is to get word "UserNameServer" ,"MQSUA02" ...
I mean I want to read Second Column and check each process status ex. "ps -ef | grep MQSUA02" so please help me to write this code
Thank you,
vikas

 

[dickiebird]

You could just use :
for linesn in `grep "UserNameServer" infile|cut -c30-40`
do
ps -ef|grep $linesn
done
- if all fields are always in those positions in your input file.

Dickie Bird (-)))

 

[vikassalvi]

Thank you very much Dickie Bird

 

[vikassalvi]

I have one problem I can't use "MQSUA02" or MQSTA01 etc etc
coz this file get generated by some application program so I want to know the way to read all words from second column and check with ps -ef coz I am not sure what it's going to write in this file and one good thing is this is fix format so I am just worry about second column variables
Please help me to resolve this issue
Thankx
vikas

 

[dickiebird]

I don't fully understand your requirements.
Do all the lines in which you're interested begin with :
BIP8099I: MQ ?
If so, grep for that, and cut -c11-17
HTH
Dickie Bird (-)))

 

[vikassalvi]

hey Dickie
here is my complete requirement
I am writing this code to start the wmqi compoents using shell and awk.
I have input file that list my all components as shown above now in my second column I have all components name
UserNameServer, MQSTA01, etc so I need to only get this second column and check each compoent with ps -ef you know what I mean for example ( ps -ef | grep MQSTA04 ) so I have to read each line and get the second column and check the status and my another req is from my input file I want to delete last line "BIP8071I: Successful command completion" I don't want this last line in my input file so could you help me to resolve this issue
Thanks for your help
vikas

 

[dickiebird]

To remove the last line of any file :

sed '$d' infile > new-file

HTH
Dickie Bird (-)))

 

[vikassalvi]

if i want grep "UserNameServer" from first line then what should i do coz cut11-17 only give me "UserNam" not the complete word "UserNameServer"

Thanks,
vikas

 

[dickiebird]

cut -c11-24 (its the start/end positions)

HTH Dickie Bird (-)))

 

[praywin]

for linesn in `grep "UserNameServer" infile|awk '{print $NF}'`
do
  echo "checking for $linesn"
  ps -ef|grep $linesn 
done

Its the same as dickiebird suggested except for 'cut' replaced with 'awk'.

if you want to do 'ps -ef....' for all lines (whether or not they contain UserNameServer) try

for linesn in `grep -v "Successful command completion" infile |awk '{print $NF}'`
do
  echo "checking for $linesn"
  ps -ef|grep $linesn
done

I am not very sure which column you want so I've put $NF for the last column. You can replace it with the column number you want.

Hope that helps.

Cheers,
Pravin.