Get a value from a group of parameters... 3

[ozi403]

Hi,

name: working_backup_group;
start time: "3:33";
options: Manual restart;
schedule: ;
work list: ;
progress file name: ;
status: idle;

name: hacivat_bonus;
start time: "3:33";
options: Manual restart;
schedule: ;
work list: ;
progress file name: ;
status: idle;

name: anadolu_group2;
start time: "3:33";
options: Manual restart;
schedule: ;
work list: ;
progress file name: ;
status: idle;

How can I get the "name:" if "status:" is idle?

 

[PHV]

A starting point:
awk '$1=="name:"{n=$2}$1=="status:"{if($2~/idle/)print n}' /path/to/input

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886

 

[ozi403]

So helpfull,
Also I understand my awk sentence's mistakes.
thanks PHV.

 

[feherke]

Hi

sed -n '/^ *name:/{s/.*://;h}; /status: idle/{g;p}' /path/to/input

Feherke.

http://rootshell.be/~feherke/

 

[Mag0007]

wow! good posts!