GD image cannot be displayed, because it contains errors.

[connectionscentres]

Hi,

I am running php version 5.0.3 and I think I have GD enabled. On the php info page for my server it says:

GD Support enabled
GD Version bundled (2.0.28 compatible)
FreeType Support enabled
FreeType Linkage with freetype
FreeType Version 2.1.7
T1Lib Support enabled
GIF Read Support enabled
GIF Create Support enabled
JPG Support enabled
PNG Support enabled
WBMP Support enabled
XBM Support enabled

However, when I try and run any GD-related functions e.g. imagecreatefromjpeg($myimage); it fails and the browser shows.
The image “

http://myserver/test/image.php”

cannot be displayed, because it contains errors.

I have made sure there are no unnecessary blank spaces and there are no syntax errors.

I have checked my apache log files and it complains that the supplied argument is not a valid Image resource.

I have therefore cut the code down to the bare minimum to just display a simple image
<?php
header ("Content-type: image/png");
$im = imagecreate (300, 300);
$white = imagecolorallocate ($im,255,255,255);
?>

Now I get no error codes in the apache log but it still doesnt display and says the same as before.

Any suggestions?

Cheers.

 

[sleipnir214]

The code you have posted will not display an image. It will create an image in your server's memory, but it will not format that image as a PNG nor will it send that image to the user's browser. You need to invoke imagepng() to perform the crucial last two steps.

Take a look at the sample code on the PHP online manual page for imagecreate(). That shows a complete example for creating an image on the fly and sending it to the browser. That example code is even sending the image to the browser as a PNG.

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TANSTAAFL!!

 

[connectionscentres]

thanks, it works, you rock!