Formating a float

[sheila11]

Hi all,

I get a float value as an output that varies is number of digits. I need to output a fixed number of digits only. How can I format it?

TIA,
Sheila

 

[Rolyat]

If you can use printf to output formated variable values to the standard output stream.

Example:
================

double dNum;
dNum = 123456.7890123

printf( "Real numbers:\n\t%f %.2f %e %E\n", dNum, dNum, dNum, dNum );

=====================
note: "%.2f" - formats a floating point number with two digits to the right of the decimal place.

You can get specifics on formating from the MSDN Library, just search on "Format Specification Fields: printf and wprintf Functions"

 

[jtm111]

When using C++ output stream:

#include <iostream>
#include <iomanip>

using namespace std;

float x = 9.283746372;
cout << setiosflags(ios::fixed) << setprecision(2) << x << endl;


9.28

 

[akashvij]

#include<iomanip>


cout<<setprecision(3)<<setiosflags(ios::fixed);

Note: When the ios::fixed flag is set, the value specified by the setprecision manipulator will be the number of digits to apper after the decimal point, not the number of significant digits.
Hope this will help you!!!