Form name in a function 3

[A1Pat]

Hi all,
I'm trying to modify this original function that is used to open a form when called:

function Do_Connect()
{	
	mySDK.WESPSDKMonitor.ClientPullingMode = 0;
	mySDK.WESPSDKMonitor.Connect();
}

and as you can see, the form name "mySDK" is located right in the beginning of the 2 lines.

What I want to do is to open more than one form instead by doing this:

function Do_Connect()
{	
	var arrCams = Channel.value.split(",");
	var x;
	for (x=0;x<arrCams.length;x++) {
          mySDK[arrCams[x]].WESPSDKMonitor.ClientPullingMode = 0;
		mySDK[arrCams[x]].WESPSDKMonitor.Connect();
	}
}

however, an error is given "mySDK is undefined" as the function goes.

I tried to hard-code by replacing the For loop with this given form name as mySDK1, mySDK2:

function Do_Connect()
{	
	var arrCams = Channel.value.split(",");
	var x;
	for (x=0;x<arrCams.length;x++) {
		mySDK1.WESPSDKMonitor.ClientPullingMode = 0;
		mySDK1.WESPSDKMonitor.Connect();
		mySDK2.WESPSDKMonitor.ClientPullingMode = 0;
		mySDK2.WESPSDKMonitor.Connect();
	}
}

and it works!

So, my question is... what's wrong here? why mySDK(x) doesn't work while mySDK1 is ok?

Please help!

 

[A1Pat]

It works now, Dan.
You forgot to tell me to replace the whole frm.WESPSDKMonitor with the cam. Thanks! Still, if you please explain the pros and cons of the eval() function.

 

[monksnake]

eval() is essentially a "cheat", it's what you do when you don't know what to do, not considered good practice to default to it.

eval() is also a very slow statement to run compared to other statements.

The only thing eval() is good for is JSON.

<.

 

[A1Pat]

Thank you monksnake for the explaination.

 

[monksnake]

No problem sir.

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