Find first character in string and return everything after.

[monkey64]

I have the string "MYPART0123456789"
I want to search it for the first occurance of a character within the range [0-9], and return everything after that (0123456789).

I have experimented with strstr, but I need to pattern match.
I know the code below won't work, but I can't get any further.

$pattern = preg_match('/^[A-Z]/', $s);
$s= 'MYPART0123456789';
echo strstr($s, $pattern);

 

[feherke]

Hi

Why not just remove the unwanted characters ?

[navy]$s[/navy][teal]=[/teal][green][i]'MYPART0123456789'[/i][/green][teal];[/teal]
[b]echo[/b] [COLOR=darkgoldenrod]preg_replace[/color][teal]([/teal][green][i]'/^[^0-9]*/'[/i][/green][teal],[/teal][green][i]''[/i][/green][teal],[/teal][navy]$s[/navy][teal]);[/teal]

Feherke.

http://free.rootshell.be/~feherke/

 

[jpadie]

but in the event that later characters can be alphanumeric too (unlikely given the OP's question but possible for future readers), this should work

$pattern = '/[\D]*(.*?)/';
preg_match($pattern, $text, $match);
echo $match[1];

 

[monkey64]

Thanks for the examples. As my part codes are always in the pattern [A-Z], followed by [0-9], I'm going with feherke's excellent preg_replace example.

Had to take a first look at regex to undertstand the caret within the square brackets. I found a good site here:

http://www.regular-expressions.info

Thanks again

 

[jpadie]

just so that future readers understand the different approaches

[^0-9]*

is identical to

[\D]*

the difference between feherke's and my solution is:
+ feherke's simply removes all non digit representations, whereas my attempt captures the latter part of the string
+ due to the removal, my solution caters for ABCD19ABCD, capturing the 19ABCD.

 

[feherke]

Hi

Actually the [tt]\D[/tt] is a character class itself, so it not needs to be enclosed in brackets ( [] ). But your expression's problem is the non-greedy question mark ( ? ), which reduces the captured part to empty string.

Feherke.

http://free.rootshell.be/~feherke/

 

[jpadie]

you are completely correct viz the \D. i had originally gone for the [^\d] for better explainability. i missed removing the brackets.
and correct on the second point also, although I had intended to add a dollar sign to the end of the string.
sloppy of me: an inherent problem in providing solutions directly into tek-tips rather than via an IDE ;-)