Find a digit

[scriptfinder]

Hi!

I am looking to find a digit in a word.

For ex:

TEXT="Number3"

I need to find digit 3 (can be any digit 'n') in the variable $TEXT.

Can anyone please help?

Thanks.

 

[Annihilannic]

A couple of ideas:

[tt]TEXT="Number3"

# Strip out any non numeric characters using sed
DIGIT=`echo $TEXT | sed 's/[^0-9]//g'`

# The same using tr
DIGIT=`echo $TEXT | tr -dc '[0-9]'`

# If it's always the last character
LENGTH=`expr length "$TEXT"`
DIGIT=`expr substr $TEXT $LENGTH 1`

# or
DIGIT=`echo $TEXT | cut -c ${LENGTH}-`[/tt]

There's probably a neat way using expr match but I don't use that much, it seems only to return whether or not there is a match, not its location in the string.

Annihilannic.

 

[scriptfinder]

Thanks a lot!!!

 

[SamBones]

The Korn shell has a pattern match operator, "@(pattern)"...

TEXT=one2three

[[ ${TEXT} = @(*[0-9]*) ]] && print "TEXT has a numeric digit in it"

 

[Annihilannic]

I was presuming he actually wanted to pull the digit out of it.

A ksh solution, again presuming the digit is on the end:

[tt]DIGIT=${TEXT##*[!0-9]}[/tt]

Annihilannic.

 

[p5wizard]

in any shell:

echo $TEXT | fold -w1 | grep '^[0-9]$' | head -1



HTH,

p5wizard