Extarcting a column from records of a file

[hello99hello]

Hello All,

I have a file (levln_ac_in.txt) with the following sample record format:
200159,,,3/21/1996,3/22/1996,,VACATION,VAC.TAKEN OTHER GRPS,,15,,,0

I am trying to extract the contents of the 8th column of each record of file levln_ac_in.txt and put it in an output file levln_dt_in.txt

Here is my effort:
#!/bin/sh

#extract column 2 from file
awk -v c=8 'NR==r { print $c }' levln_ac_in.txt > levln_dt_in.txt

my output file should contain the following format sample records:
VAC.TAKEN OTHER GRPS

However the output file is retunring zero, please help.

 

[vgersh99]

nawk -F, -v c=8 '{print $c}' levln_ac_in.txt > levln_dt_in.txt

vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[hello99hello]

Thanx,

I was able to ommit the n and use the following:

awk -F, -v c=8 '{print $c}' levln_ac_in.txt > levln_dt_in.txt

It works

 

[Salem]

Scary deja vue

http://www.tek-tips.com/viewthread.cfm?qid=912581

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