exporting a variable out of a function so the rest of the script can s

[DanNJ]

Why won't this work? How can I make it work?

Start Script:
a1()(
var=2; export var
)
echo $var

 

[sampsonr]

First Problem: Functions are defined curly braces, not parentheses, as shown below

a1() {
var=2; export var
}

Second Problem: You never actually call the function so the variable never gets set.

 

[DanNJ]

I forgot to call it when I typed it here, it seems that () keep the variables within the function but {} let them out.

interesting.