exctract file according header,column and row

[toax]

I am beginer in programing with awk, I have file 1 :

1 2 3
3 3 3 3 3 3 2 3
4 4 4 4 4 4 1 4
7 7 6
5 5 5 5 5 5 5 5
6 6 6 6 6 6 6 6
7 7 7 7 7 7 7 7
3 4 2
1 1 1 1 1 1 1 5
2 2 2 2 2 2 2 3
4 4 4 4 4 4 4 4
6 6 6 6 6 6 6 6

and I would like to extract file 1 according header, row and coloumn. This file will generete file 2 , file 3 and file 4 :

File 2 :
3 3 3 3 3 3 2 3
4 4 4 4 4 4 1 4

File 3 :
5 5 5 5 5 5 5 5
6 6 6 6 6 6 6 6
7 7 7 7 7 7 7 7

File 4 :
1 1 1 1 1 1 1 5
2 2 2 2 2 2 2 3
4 4 4 4 4 4 4 4
6 6 6 6 6 6 6 6

is it possible to do with awk ?
Thanks in advance

 

[PHV]

A starting point:

awk 'BEGIN{seq=1}NF==3{out="file"(++seq);next}{print >out}' file1

Hope This Helps, PH.
FAQ219-2884
FAQ181-2886

 

[toax]

Thanks for your reply, but this code only produce one file ("file"), isn't? the problem is I want to produce saveral files (file 2 , 3, and 4) from file 1. I am a really beginer in awk programing.

 

[PHV]

this code only produce one file
Really ?
Did you even try it ?

 

[toax]

Thank @PHV, yes this code able to produce several files, I'm sorry it was mistake, so I can learn more about awk, Thanks again for your kind help