Error when trying to retrieve data from datagrid

[suicidaltendencies]

Error:
Object reference not set to an instance of an object.

Code:
lblDetailsMore.Text =((System.Web.UI.WebControls.Label)dgEditAppointments.SelectedItem.FindControl("lblName")).Text;

ASP Page:
<asp:templatecolumn headerstyle-wrap="false" HeaderText="Customer Name" itemstyle-verticalalign="top">
<itemtemplate>
<asp:label id="lblName"><%# DataBinder.Eval(Container.DataItem, "CustomerName") %></asp:label>
</itemtemplate>
</asp:templatecolumn>

Thanks,
Harold

 

[dragonwell]

Find the label control in the template column during the ItemDataBound event of the DataGrid.

Code:
protected void dgEditAppointments_ItemDataBound(object sender, DataGridItemEventArgs e){
    Label lblName = (Label)e.Item.FindControl("lblName");
    if(!(lblName==null)){
        this.lblDetailsMore.Text = lblName.Text;
    }
}

ASP Page:
<asp:datagrid runat="server" id="dgEditAppointments" OnItemDataBound="dgEditAppointments_ItemDataBound">
<Columns>
<asp:templatecolumn headerstyle-wrap="false" HeaderText="Customer Name" itemstyle-verticalalign="top">
    <itemtemplate>            
        <asp:label id="lblName"><%# DataBinder.Eval(Container.DataItem, "CustomerName") %></asp:label>
    </itemtemplate>                
</asp:templatecolumn>
</Columns>
</asp:datagrid>

HTH

 

[suicidaltendencies]

This doesn't work for me. What I need to happen is when I click the "Select" button column I want a label to display what is in the selected 4th column. The forth column is a label.

Thanks,
James

 

[suicidaltendencies]

This doesn't work for me. What I need to happen is when I click the "Select" button column I want a label to display what is in the selected 4th column. The forth column is a label.

Thanks,
Harold

 

[LV]

Add runat=server to the Label tag:

<asp:templatecolumn headerstyle-wrap="false" HeaderText="Customer Name" itemstyle-verticalalign="top">
    <itemtemplate>            
        <asp:label id="lblName" runat=server><%# DataBinder.Eval(Container.DataItem, "CustomerName") %></asp:label>
    </itemtemplate>                
</asp:templatecolumn>

When you click an item in the datagrid, the ItemCommand event will fire. In the code behind event handler, you can get a reference to the Label in the clicked row.

private void DataGrid1_ItemCommand(object source, System.Web.UI.WebControls.DataGridCommandEventArgs e)
{
  Label lbl = (Label)e.Item.FindControl("lblName");
  string text = lbl.Text;
}