double

[skabdulravoof]

is there any difference between
double (i*j)
(double) i*j


thanks for ur time

 

[Salem]

Yes there is a difference.


--

 

[skabdulravoof]

can u expalin the difference plzzz

 

[Salem]

Without declarations and values for i and j, no.


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[teriviret]

double (i*j)" multiplies i by j, then converts the result into a double.

"(double) i*j" converts i into a double, then multiplies by j.

 

[teriviret]

And actually, "double (i*j)" should be "(double) (i*j)" otherwise it is a syntax error.

 

[ArkM]

teriviret,
double(i*j) is OK cast in C++...

Let's try:

#include <limits>
#include <iostream>
...
const int maxint = numeric_limits<int>::max();
...
double bad = double(i*j);// integer overflow!..
double ok = (double)i*j; // same as ((double)i)*j...
cout << bad << " " << ok << endl;

 

[teriviret]

Right you are, my bad.