Document() 1

[JontyMC]

When you use document() in a for-each, how do you refer to the original document?

<xsl:for-each select="document('mydoc.xml')">
  <xsl:value-of select="????"/>
</xsl:for-each>

 

[JontyMC]

Any ideas? I really need to refer to the original context document of the stylesheet within the for-each.

 

[flumpy]

hmm why not refer to document in a variable?

<xsl:variable name="myextdoc">
<xsl:copy-of select="document('mydoc.xml')"/>
</xsl:variable>

....

<xsl:for-each select="$myextdoc/*"/>
<xsl:value-of select="internal-node/*[local-name()=./text()"/>
</xsl:for-each>

...

however i'm still looking for a better solution, i know u dont like using variables

matt

 

[JontyMC]

Haha. Yes, I'd rather not use variables if possible.

I thought document('') would work, but that gives you the root of the actual stylesheet.

I want to do something like document(..) or document(previous-document). I'm sure it must be possible.

 

[flumpy]

found this:

http://www.xslt.com/html/xsl-list/2005-02/msg01155.html

which says doing it the other way around, and storing your current document in a variable

..

<xsl:variable name="inputdoc" select="/"/>

..

still not found a non-variable method yet

 

[flumpy]

hmmm just had another thought.. don't know how efficient it is but assuming the current input document is called "myinput.xml" and the other xml doc is called "theother.xml" you could do this:

<xsl:for-each select="document('theother.xml')/*">
<xsl:value-of select="document('myinput.xml')/*[local-name()=./text()"/>
</xsl:for-each>

again as i say, it's probably not that efficient.

matt

 

[JontyMC]

Thanks for the efforts matt. After reading posts off that forum I think I'll have to give up the ghost and use a variable.