Division operator that returns an integer

[nhungr]

Hello.

Is there an operator or function in C++ that allows you to divide two numbers and return just the integer part (ie. the number on the left side of the decimal point)? The opposite of the modulus (%) operator!

Examples:
7 / 2 would return the integer 3
14 / 3 would return the integer 4

There should be no rounding up to the nearest integer!

Thanks,
Nikolai.

 

[uolj]

If you store or cast the return value to an int, then only the integer part will be there. If your operands are integers, then this is done for you.

There is also a function in <cmath> called floor that will work for doubles and can be used on the result of double division.

If you might be working with negative numbers pay special attention to how these two solutions handle them.

 

[der7]

Hi,

I think the function floor() will work for you. It will round down to the nearest integer.

Regards,

David