DIfference between "or" and "||"

[dkyrtata]

Why do the following boolean expressions return a different result? The first one returns 1 (true), which is correct.

$hh=23; 
$dd=32;

$bool1= ($hh>23) || ($dd>31);
$bool2= ($hh>23) or ($dd>31);

print "bool1=$bool1\n";
print "bool2=$bool2\n";

 

[prex1]

Binary "or" returns the logical disjunction of the two surrounding expressions. It's equivalent to || except for the very low precedence.

The second expression is doing this

[tt]($bool2= ($hh>23)) or ($dd>31);[/tt]

Franco

http://www.xcalcs.com

: Online engineering calculations

http://www.megamag.it

: Magnetic brakes for fun rides

http://www.levitans.com

: Air bearing pads

 

[dkyrtata]

Thanks, I confirmed it by enclosing the entire right side in brackets. Prior to Perl 5, there was only the "||" operator. The "or" was implemented in Perl 5, but I thought that it was just a synonym having the exact behavior.

 

[rharsh]

Take a look at perldoc perlop for all the operator's precedence.