delete zeros in a row

[tonivm]

hi everybody:
Could anybody tell me how I can from a row which is:

00
01
02
03
04
05
06
07
08
09
10
11
......

delete the first zero and then I will have:
1
2
3
4
5
6
7
8
9
10
11
........

Thanks in advance and cheers.

 

[PHV]

sed 's/^0//' /path/to/input > output

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886

 

[gargamel100]

Try this,

sed '2,10 s/0/ /' input_file | awk '{if($1 !~/^0/) print $1 }'> output_file

input_file=contains a zeros
output_file=without zeros

tested with awk.

Regards

 

[feherke]

Hi

Nice try gargamel100, but both [tt]sed[/tt] and [tt]awk[/tt] can solve this alone :

sed 's/^0\+//;/^$/d' /input/file

[gray]# or[/gray]

awk '$0{print $0+0}' /input/file

And to appreciate your speed optimization :

sed '1,/^[^0]/{s/^0\+//;/^$/d}' /input/file

[gray]# or[/gray]

awk 'NR==1,!/^0/{if($0)print $0+0;next}1' /input/file

Tested with GNU [tt]sed[/tt], [tt]gawk[/tt] and [tt]mawk[/tt].

Feherke.

http://rootshell.be/~feherke/

 

[olded]

Just for grins:

!/bin/ksh

typeset -i x

while read x
do
echo $x
done < in.file > out.file

 

[feherke]

Hi

Sorry, I found no suitable grin emoticon in Tek-Tips' collection.

[red]#[/red]!/bin/ksh

typeset -i x

while read x
do
[red]test $x -gt 0 &&[/red] echo $x
done < in.file > out.file

Feherke.

http://rootshell.be/~feherke/