Counting in hex

[hopwon]

I'm writing a script to create target and lun numbers for disks.
The script needs to start with a number and count to 7 printing the count. Then reset the second number to 0 and increment the first number and print the results.
It must be in hex too.
e.g.
0A 00
0A 01
0A 02
....
0A 07
0B 00
0B 01
0B 02 etc

I can do this with a long shell script but was hoping someone can suggest a more efficent way with AWK?

thanks

 

[p5wizard]

awk on AIX (dont know about others) doesn't seem to understand hex numbers in input so:

awk 'BEGIN{
 target=10; # would have liked: target=0xa;
 lun=0      # 0x00
 while (target <= 31) { # 0x1f
  while (lun <= 7) {    # 0x07
   printf "%02X %02X\n", target, lun
   lun++
  }
  target++
  lun=0
 }
}'

HTH,

p5wizard

 

[hopwon]

Awesome! Thanks for this man it works exactly as i wanted.
Saved me loads of work!

Cheers

 

[p5wizard]

(korn) shell script isn't too long either:

(( tgt=10 ))
(( lun=0 ))
while (( tgt <= 31 ))
do
 while (( lun <= 7 ))
 do
  printf "%02X %02X\n" $tgt $lun
  (( lun=lun+1 ))
 done
 (( tgt=tgt+1 ))
 (( lun=0 ))
done

HTH,

p5wizard