Converting byte array to int array

[jmofthenorth]

Hi.
I have a Byte array that I'd like to convert to long ints. Is there a quick way of doing this.
essentially I'd like to take bytes: bytearray[0], bytearray[1], bytearray[2], bytearray[3] and combine them to form one int32 (here bytearray[3] has the lsb and [0] the msb).
There must be a method already implemented in C# to do this...
jm

 

[earthandfire]

This should enable you to do what you need:

http://www.thescripts.com/forum/thread247247.html

Hope this helps.

 

[jmofthenorth]

That linked helped, but it was confusing. What I was looking for, for anyone who's interested is the method BitConverter.ToInt(); which allows one to select a subsection from a byte array and the convert it to an Int.

 

[lardyboy]

I’m just a novice C# programmer …

byte[] dog= {2,3,4,5,6,7};

long result= dog[0];
result = ( result<<8 ) + dog[1];
result = ( result<<8 ) + dog[2];
result = ( result<<8 ) + dog[3];

unsafe{
byte* dogArray= (byte*)&result;
byte a= dogArray[0];
byte b= dogArray[1];
byte c= dogArray[2];
byte d= dogArray[3];
}

First I have created a byte array “dog”.
I have constructed a long from the first four bytes of dog in a safe manner. Note that byte zero is the most significant.

Now, since I wish to be daring and use pointers, I need an “unsafe” code block. I also need to set the “/unsafe” switch in the compiler (see compiler documentation).

Now I can extract the byte values from the long. It turns out that they are saved least significant byte first.

Translating a byte array into a long array is not smart because a long array has to be word aligned in memory. You need to get the long array first, and copy the bytes into it that way.

 

[lardyboy]

Ooops. I see now you answered your own question!