Convert day of year 1

[ecannizzo]

I need to convert the day of the year (which I have) to a month and a day. Is there a function that will do this for me, or anyone know of a way?

Thanks!

 

[CDuddley]

MFC has some cool classes like CTime and CTimeSpan you can check more out at

http://msdn.microsoft.com/

Hope that helps.

-CDudd

 

[Zyrenthian]

create an array of months.

int months[12];

determine if it is a leap year and set months[1] appropriately.

int x = 0;

int i;
for(i = 0;i<12;i++)
{
   x += months[i];
  
   if(x> value_in_days)
       break;
}

ok... so we know the month is at i

now we need to figure out what day it is.

that should just be x-value_in_days;


I think that is the gist of it.

Matt

 

[Zyrenthian]

the months array contains the days per month

Matt

 

[ecannizzo]

Thanks for your help but I'm a little confused. Lets say I know its day 300 of year 2001 I use month[300]?

 

[CDuddley]

No each element in the month array contains the days per month. So just search through the array (using that loop he wrote) until you find your day .

-CDudd

 

[Jeffray]

The code below will meet your needs:

CTime tm(2001,1,1,0,0,0);
tm += CTimeSpan(300,0,0,0);
int nYear = tm.GetYear();
int nMonth = tm.GetMonth();
int nDay = tm.GetDay();

 

[ecannizzo]

When I try to include afx.h I get linking errors. Any idea why?

 

[ecannizzo]

I figured it out. Thanks for all your help!!