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comma function for Indian number system...

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visitnag

Programmer
Sep 21, 2006
15
IN
Hi

Is there any shorter way to use a comma separator for Indian Number system?
its like ##,##,##,##,###.##. I have written the following code but its quite lengthy...
function comma(n){
if(length(n) <= 3 ){ n = n}else
if(length(n) == 4 ){ n = substr(n,1,1)","substr(n,2)}else
if(length(n) == 5 ){ n = substr(n,1,2)","substr(n,3)}else
if(length(n) == 6 ){ n = substr(n,1,1)","substr(n,2,2)","substr(n,4)}else
if(length(n) == 7 ){ n = substr(n,1,2)","substr(n,3,2)","substr(n,5)}else
if(length(n) == 8 ){ n = substr(n,1,1)","substr(n,2,2)","substr(n,4,2)","substr(n,6)}else
if(length(n) == 9 ){ n = substr(n,1,2)","substr(n,3,2)","substr(n,5,2)","substr(n,7)}else
if(length(n) == 10){ n = substr(n,1,1)","substr(n,2,2)","substr(n,4,2)","substr(n,6,2)","substr(n,8)}else
if(length(n) == 11){ n = substr(n,1,2)","substr(n,3,2)","substr(n,5,2)","substr(n,7,2)","substr(n,9)}else
if(length(n) == 12){ n = substr(n,1,1)","substr(n,2,2)","substr(n,4,2)","substr(n,6,2)","substr(n,8,2)","substr(n,10)}else
if(length(n) == 13){ n = substr(n,1,2)","substr(n,3,2)","substr(n,5,2)","substr(n,7,2)","substr(n,9,2)","substr(n,11)}else
n=n
return(n)

Thank you.
 
Hi

For integers this should do it for any size :
Code:
[COLOR=orange]function comma[/color][teal]([/teal]n          [teal],[/teal] nn[teal])[/teal]
[teal]{[/teal]
    [b]while[/b] [teal]([/teal]n [teal]!=[/teal] nn [teal]=[/teal] [COLOR=orange]gensub[/color][teal]([/teal][fuchsia]/([[:digit:]])([[:digit:]]{3}$|[[:digit:]]{2},)/[/fuchsia][teal],[/teal] [i][green]"[/green][/i][lime]\\[/lime][i][green]1,[/green][/i][lime]\\[/lime][i][green]2"[/green][/i][teal],[/teal] [purple]1[/purple][teal],[/teal] n[teal])) {[/teal]
        n [teal]=[/teal] nn
    [teal]}[/teal]
 
    [b]return[/b] n
[teal]}[/teal]

For fractional part I did not got the rule.


Feherke.
feherke.github.io
 
Thank you very much...but...sorry! could you please explain the syntax. I have gone through string manipulation functions in gnu awk manual, but could not understand your syntax.
 
Hi

There is nothing special. Let us rewrite it abit :
Code:
[COLOR=orange]function comma[/color][teal]([/teal]n          [teal],[/teal] new_n[teal])[/teal]
[teal]{[/teal]
    new_n [teal]=[/teal] [COLOR=orange]gensub[/color][teal]([/teal][fuchsia]/([[:digit:]])([[:digit:]]{3}$|[[:digit:]]{2},)/[/fuchsia][teal],[/teal] [i][green]"[/green][/i][lime]\\[/lime][i][green]1,[/green][/i][lime]\\[/lime][i][green]2"[/green][/i][teal],[/teal] [purple]1[/purple][teal],[/teal] n[teal])[/teal]

    [b]while[/b] [teal]([/teal]n [teal]!=[/teal] new_n[teal]) {[/teal]
        n [teal]=[/teal] new_n

        new_n [teal]=[/teal] [COLOR=orange]gensub[/color][teal]([/teal][fuchsia]/([[:digit:]])([[:digit:]]{3}$|[[:digit:]]{2},)/[/fuchsia][teal],[/teal] [i][green]"[/green][/i][lime]\\[/lime][i][green]1,[/green][/i][lime]\\[/lime][i][green]2"[/green][/i][teal],[/teal] [purple]1[/purple][teal],[/teal] n[teal])[/teal]
    [teal]}[/teal]

    [b]return[/b] n
[teal]}[/teal]
[ul]
[li]We insert each comma one by one in a [tt]while[/tt] loop.[/li]
[li]The loop is repeated as long as another comma is added.[/li]
[li]To know when no comma was added so is time to stop, we store the result of the modification attempt in a local variable new_n.[/li]
[li]Each time the value was modifier, we assign the new_n to n, and repeat the modification attempt to obtain a fresh new_n.[/li]
[li]The regular expression used in [tt]gensub()[/tt] could be written shorter as [tt]/([0-9])([0-9]{3}$|[0-9]{2},)/[/tt] ( or in other languages even [tt]/(\d)(\d{3}$|\d{2},)/[/tt] ).[/li]
[li]The regular expressions are matching the number like this :[ul]
[li][pre]
[COLOR=green #9f9]\1[/color][COLOR=blue #99f]\2[/color]
[green]│[/green][blue]╭┴╮[/blue]
[highlight]123456[/highlight][COLOR=green #9f9]7[/color][COLOR=blue #99f]890[/color]
[green]│[/green][blue]╰┬╯[/blue]
[green]│[/green] [blue]╰────────────╮[/blue]
[green]╭────┴────╮[/green] [blue]╭──────┴──────╮[/blue]
/([COLOR=green #9f9][[:digit:]][/color])([COLOR=blue #99f][[:digit:]]{3}$[/color]|[[:digit:]]{2},)/
[/pre][/li]
[li][pre]
[COLOR=green #9f9]\1[/color][COLOR=blue #99f]\2[/color]
[green]│[/green][blue]╭┴╮[/blue]
[highlight]12[/highlight][COLOR=green #9f9]3[/color][COLOR=blue #99f]45,[/color][highlight]67,890[/highlight]
[green]│[/green][blue]╰┬╯[/blue]
[green]│[/green] [blue]╰────────────────────────────╮[/blue]
[green]╭────┴────╮[/green] [blue]╭──────┴──────╮[/blue]
/([COLOR=green #9f9][[:digit:]][/color])([[:digit:]]{3}$|[COLOR=blue #99f][[:digit:]]{2},[/color])/
[/pre][/li]
[/ul][/li]
[/ul]

Feherke.
feherke.github.io
 
Hi

Thinking again, would be simpler and faster with a [tt]for[/tt] loop and [tt]substr()[/tt] :
Code:
[COLOR=orange]function comma[/color][teal]([/teal]n          [teal],[/teal] i[teal])[/teal]
[teal]{[/teal]
    [b]for[/b] [teal]([/teal]i [teal]=[/teal] [b]index[/b][teal]([/teal]n[teal],[/teal] [i][green]"."[/green][/i][teal]) ?[/teal] [b]index[/b][teal]([/teal]n[teal],[/teal] [i][green]"."[/green][/i][teal])[/teal] - [purple]3[/purple] [teal]:[/teal] [b]length[/b][teal]([/teal]n[teal])[/teal] - [purple]2[/purple][teal];[/teal] i [teal]>[/teal] [purple]1[/purple][teal];[/teal] i -[teal]=[/teal] [purple]2[/purple][teal]) {[/teal]
        n [teal]=[/teal] [b]substr[/b][teal]([/teal]n[teal],[/teal] [purple]0[/purple][teal],[/teal] i - [purple]1[/purple][teal])[/teal] [i][green]","[/green][/i] [b]substr[/b][teal]([/teal]n[teal],[/teal] i[teal])[/teal]
    [teal]}[/teal]

    [b]return[/b] n
[teal]}[/teal]


Feherke.
feherke.github.io
 
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