checking character strings with an if statement

[StarMechLX]

ok... this is what i want my code do to:

if the variable 'name' is "the same as(i'm not sure if there is the identical operator in cpp)" this string: 'StarMech'

and this is what i have:

if (name == "StarMech&quot
{
cout << &quot;Verification Success!&quot; << endl;
return 0;
} else {
cout << &quot;Verification Failed!&quot; << endl;
return 0;
}

i already have the character declaration and everything worked out, i just need this one peice of the code to work... whyyyy!!!!????!?!?!?!?

 

[sskumar]

hi starmechLx,
why u need to write this complex code?. u can very well go for strcmp() funtion know?

S.Senthil Kumar.

 

[StarMechLX]

Can you explain please? i'm a newb when it comes to programming period. I just wanna have it to where it says like, if his input is 'look' like in a MUD, it posts the details of the room, instead of having to cout a bunch of lines saying &quot;1 - Look around, 2 - blah blah blah ect. ect.&quot;

 

[VincentP]

It is not possible to write name == &quot;some string&quot; in C/C++. Thus you need to use functions such as strcmp (string compare).

From MSDN (very useful reference, msdn.microsoft.com)

int strcmp( const char *string1, const char *string2 );

Return Value

The return value for each of these functions indicates the lexicographic relation of string1 to string2.

Value Relationship of string1 to string2
< 0 string1 less than string2
0 string1 identical to string2
> 0 string1 greater than string2


For what you want to do:

if( strcmp(name, &quot;My string&quot == 0 )
{
// identical strings
}
else
{
// different
}


Vincent

 

[palbano]

>> It is not possible to write name == &quot;some string&quot;

Well that's not entirely accurate. If the variable “name” is a class type that defines an equality operator where the second parameter is defined as &quot;const char*&quot;, it is entirely possible.

-pete