char declaration

[developer155]

I am trying to declare a char variable like this:
char varname = (char)32;

so basically I need number 32 to become varname of type char (I need to pass it to one string function, replace)

but after declaration when I walk through the code I notice that after declaration varname has value '', instead of '32'.

Am I not declaring it correctly?

thamks!!

 

[Cagliostro]

the char with code 32 is just the space
So following three lines are identically equivalent:
char xx = 32;
char xx = '\32';
char xx = ' ';

Ion Filipski

 

[Cagliostro]

By the way, if you want to make a string which equals to "32" (two characters '3' and '2') you should do like this:

String x = "32";

Ion Filipski

 

[developer155]

Something is still wrong, I did this: char big = '\32';
and when I walked thru the code I saw that big was assigned this character | instead of 32. What is going on????

thanks!!!

 

[Cagliostro]

It looks a bit strange to me, I've got the same results. Java specifics are a bit different than C++ specifics...

Ion Filipski

 

[hologram]

char big ='\32' means octal 32, which is = 3*8+2 = 26 in decimal or 1A in hex.

char big ='\u0032' means unicode 32 which is in hex.

 

[Cagliostro]

anyway, the space character is 32dec or 20hex

Ion Filipski

 

[developer155]

OK, still having problems: I declared this way:
char big='\u0032';
char small='\u0016';

as you see I need to declare 32 and 16 as char. When I run, program assigns 2 to big (not 32) and | to small (not 16). What I am I doing wrong now??

thanks

 

[hologram]

Because, like Ion Filipski says :
'\u0020" is the space character

'\u0032' is the character '2'

If you need "32" then you need two chars, you can't get it in 1 char :
'\u0033' is the character '3'
'\u0032' is the character '2'

You can find the ascii table at :

http://www.asciitable.com/

 

[jurchi]

try '\u3332'

 

[stefanwagner]

or

char[] big = new char[2];
char[0] big = '3';
char[1] big = '2';