cgi URL param driving me mad. Please help!

[cantfindausername]

Hi,

For some reason I can't get a param that I'm passing in the URL to work, and its driving me nuts.

I have a "cgi-bin/test.cgi?selection=R33" URL that I am trying to get to work.

When I manually define $selection = "R33"; it works fine. When I try to pass R33 as a parameter on the URL (as above)it gives me an error which I can't figure out.

#my $selection="R33";
my $query = CGI->new();
my $selection = $query->param('selection');

I know its going to be something simple that I haven't figured out yet as this is my first attempt.

Any advice would be super though.

Thanks in advance,
Anthony

 

[audiopro]

What is the error?
Have you tried chomping it?

Keith

http://www.studiosoft.co.uk

 

[cantfindausername]

Not sure what the error was. Couldn't get anything from the log.

I've got to the bottom of it though after trawling google and sites all day. It seemed I was missing the: use CGI 'param'; - it all now seems to be working. Will play around a bit more now.

SO for search purposes the solution was

use CGI 'param';
$selection = param('selection');
$datafile="gtr_data.csv";

href="/cgi-bin/test.cgi?selection=R33"

Cheers,
Ant

 

[Kirsle]

That's weird. Object-oriented CGI should work fine. I use something along the following lines in most of my CGI scripts...

#!/usr/bin/perl -w

use CGI;
use URI::Escape;

my $cgi = new CGI;
my $query = {};

foreach my $what ($cgi->param) {
   my $is = $cgi->param($what);
   $is = uri_unescape ($is);
   $query->{$what} = $is;
}

print "Content-Type: text/html\n\n";
print $query->{selection}; # or whatever

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