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can't create independent variables?

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jemminger

jemminger

Programmer
Jun 25, 2001
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this set of functions is intended to return the position of an element on the page:
[tt]
function getCoords(o) {
setCoords(o);
var xx = new Number(window.coords.x);
var yy = new Number(window.coords.y);
var tmp = {x:xx, y:yy};
//window.coords = null;
return tmp;
}

function setCoords(o) {
if (!window.coords)
window.coords = new Coords(o.offsetLeft, o.offsetTop);
else window.coords.add(o.offsetLeft, o.offsetTop);

if (o.tagName == "BODY") {
return window.coords;
}
else {
getCoords(o.offsetParent);
}
}
function Coords(x,y) {
this.x = x;
this.y = y;
return this;
}
Coords.prototype.add = function(x,y) {
this.x += x;
this.y += y;
}
[/tt]

usage:
<body>
<form>
<table>
<tr>
<td>
<input type=&quot;button&quot;
value=&quot;getCoords();&quot;
onclick=&quot;c = getCoords(this); alert(c.x + ',' + c.y)&quot; />
</td>
</tr>
</table>
</form>
</body>

the problem is that in getCoords(), if you uncomment the line &quot;//window.coords = null;&quot;, then it destroys the vars xx and yy inside tmp!!!

what am i doing wrong?



=========================================================
try { succeed(); } catch(E) { tryAgain(); }
-jeff
 
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nevermind...ended up solving it a different way!



=========================================================
try { succeed(); } catch(E) { tryAgain(); }
-jeff
 
Upvote 0 Downvote
x and y are (sub)properties of the window property coords. When you set window.coords = null you do indeed distroy any properties it had. You might have wanted this...

window.coords.x = null;
window.coords.y = null;

Good Luck! [thumbsup2]
WindUp
 
Upvote 0 Downvote
what i was trying to do is store those two values in new vars, and destroy the original object...how can i do this?

=========================================================
try { succeed(); } catch(E) { tryAgain(); }
-jeff
 
Upvote 0 Downvote
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