Calculating time

[jwant]

I need to be able to look at what time it currently is and determine if a specified amount of time has passed, say 15 minutes.

 

[PHV]

In ksh you can play with the

 SECONDS

buil-in variable.
Otherwise you can use the

 date

command.
man ksh
man date

Hope This Help
PH.

 

[jwant]

Let me clarify. I want a job to run every fifteen minutes. So, it will run on 0, 15, 30, and 45 of each hour. How do I do this? I know how to get seconds and minutes and hours and all that. But how do your calculated that fifteen minutes or say 5 minutes have passed?

 

[vgersh99]

man cron

vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[PHV]

man crontab

Hope This Help
PH.

 

[jwant]

Ok, this is what I did I used the function modulus.

if [ `expr $MIN % 15` = 0 ] # this determins if there is
# a remainder.
then
succcess
else
fail
fi

By determining the remainder I can tell whether the minutes are a multiple of 15 or not. So, 30 will return a 0 and so on. I hope this helps someone else.

 

[SamBones]

Listen to the responses! This kind of thing is done with cron. You just need to create a script to do what you want one time with no time logic built into it. Then put an entry in your crintab like this...

   0,15,30,45 * * * * myscript.sh >> myscript.log 2>&1

This will run [tt]myscript.sh[/tt] every 15 minutes.

Otherwise you need to either keep submitting your script every minute and have it fail when it's not MOD 15 = 0, or have it in some busy loop.

Believe me, cron is cleaner and more reliable than trying to code this yourself.

Hope this helps.